Pharmaceutical Calculation question? - pharmaceutical calculations by ansel free download
What is the final concentration of solution of sodium chloride by mixing 100 ml 0.9% w / v, 200 ml of 0.45% w / v 300 ml, and 0.2% w receive / v
Sunday, February 21, 2010
Pharmaceutical Calculations By Ansel Free Download Pharmaceutical Calculation Question?
2 comments:
100 ml 0.9% NaCl = 900 mg
200 ml 0.45% NaCl = 900 mg
300 ml NaCl 0.2% = 600 mg
2400mg total of 600ml of NaCl
600ml / 2400mg = 100 ml / mg x
x = (2400mg * 100 ml) / 600 ml
x = 400 mg
Therefore, the final concentration of 0.4% m / v is
Three saline solutions:
1) 0.9% w / v = 0.9 grams per 100 ml
2) 0.45% w / v = 0.45 grams per 100 ml
3) 0.2% w / v = 0.2 grams per 100 ml
The total volume = 100 ml + 200 ml + 300 ml = 600 ml
100 ml 0.9% m / v = 0.9 g NaCl
200 ml of 0.45% w / v = 0.9 g (0.45 x 2) NaCl
300 ml of 0.2% m / v = 0.6 g (0.2 x 3) NaCl
Total mass of NaCl = 0.9 g + 0.9 g + 0.6 g = 2.4 g
The final concentration = 2.4 g / 600 ml = 0.4g/100ml = 0.4% (w / v)
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